Integrand size = 34, antiderivative size = 225 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=-8 a^4 (A-i B) x+\frac {8 a^4 (i A+B) \log (\cos (c+d x))}{d}+\frac {8 a^4 (A-i B) \tan (c+d x)}{d}+\frac {4 a^4 (i A+B) \tan ^2(c+d x)}{d}-\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d} \]
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Time = 1.01 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.147, Rules used = {3675, 3673, 3609, 3606, 3556} \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=-\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d}+\frac {4 a^4 (B+i A) \tan ^2(c+d x)}{d}+\frac {8 a^4 (A-i B) \tan (c+d x)}{d}+\frac {8 a^4 (B+i A) \log (\cos (c+d x))}{d}-8 a^4 x (A-i B)-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d} \]
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Rule 3556
Rule 3606
Rule 3609
Rule 3673
Rule 3675
Rubi steps \begin{align*} \text {integral}& = \frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}+\frac {1}{6} \int \tan ^2(c+d x) (a+i a \tan (c+d x))^3 (3 a (2 A-i B)+3 a (2 i A+3 B) \tan (c+d x)) \, dx \\ & = \frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}+\frac {1}{30} \int \tan ^2(c+d x) (a+i a \tan (c+d x))^2 \left (6 a^2 (8 A-7 i B)+6 a^2 (12 i A+13 B) \tan (c+d x)\right ) \, dx \\ & = \frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d}+\frac {1}{120} \int \tan ^2(c+d x) (a+i a \tan (c+d x)) \left (6 a^3 (68 A-67 i B)+6 a^3 (92 i A+93 B) \tan (c+d x)\right ) \, dx \\ & = -\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d}+\frac {1}{120} \int \tan ^2(c+d x) \left (960 a^4 (A-i B)+960 a^4 (i A+B) \tan (c+d x)\right ) \, dx \\ & = \frac {4 a^4 (i A+B) \tan ^2(c+d x)}{d}-\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d}+\frac {1}{120} \int \tan (c+d x) \left (-960 a^4 (i A+B)+960 a^4 (A-i B) \tan (c+d x)\right ) \, dx \\ & = -8 a^4 (A-i B) x+\frac {8 a^4 (A-i B) \tan (c+d x)}{d}+\frac {4 a^4 (i A+B) \tan ^2(c+d x)}{d}-\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d}-\left (8 a^4 (i A+B)\right ) \int \tan (c+d x) \, dx \\ & = -8 a^4 (A-i B) x+\frac {8 a^4 (i A+B) \log (\cos (c+d x))}{d}+\frac {8 a^4 (A-i B) \tan (c+d x)}{d}+\frac {4 a^4 (i A+B) \tan ^2(c+d x)}{d}-\frac {a^4 (92 A-93 i B) \tan ^3(c+d x)}{60 d}+\frac {i a B \tan ^3(c+d x) (a+i a \tan (c+d x))^3}{6 d}-\frac {(2 A-3 i B) \tan ^3(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{10 d}-\frac {(12 A-13 i B) \tan ^3(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{20 d} \\ \end{align*}
Time = 1.83 (sec) , antiderivative size = 138, normalized size of antiderivative = 0.61 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {a^4 \left (-92 i A-93 B-480 i (A-i B) \log (i+\tan (c+d x))+480 (A-i B) \tan (c+d x)+240 (i A+B) \tan ^2(c+d x)-20 (7 A-8 i B) \tan ^3(c+d x)+(-60 i A-105 B) \tan ^4(c+d x)+12 (A-4 i B) \tan ^5(c+d x)+10 B \tan ^6(c+d x)\right )}{60 d} \]
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Time = 0.19 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.75
method | result | size |
derivativedivides | \(\frac {a^{4} \left (-\frac {4 i B \left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {B \left (\tan ^{6}\left (d x +c \right )\right )}{6}-i A \left (\tan ^{4}\left (d x +c \right )\right )+\frac {A \left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {8 i B \left (\tan ^{3}\left (d x +c \right )\right )}{3}-\frac {7 B \left (\tan ^{4}\left (d x +c \right )\right )}{4}+4 i A \left (\tan ^{2}\left (d x +c \right )\right )-\frac {7 A \left (\tan ^{3}\left (d x +c \right )\right )}{3}-8 i B \tan \left (d x +c \right )+4 B \left (\tan ^{2}\left (d x +c \right )\right )+8 A \tan \left (d x +c \right )+\frac {\left (-8 i A -8 B \right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (8 i B -8 A \right ) \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(168\) |
default | \(\frac {a^{4} \left (-\frac {4 i B \left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {B \left (\tan ^{6}\left (d x +c \right )\right )}{6}-i A \left (\tan ^{4}\left (d x +c \right )\right )+\frac {A \left (\tan ^{5}\left (d x +c \right )\right )}{5}+\frac {8 i B \left (\tan ^{3}\left (d x +c \right )\right )}{3}-\frac {7 B \left (\tan ^{4}\left (d x +c \right )\right )}{4}+4 i A \left (\tan ^{2}\left (d x +c \right )\right )-\frac {7 A \left (\tan ^{3}\left (d x +c \right )\right )}{3}-8 i B \tan \left (d x +c \right )+4 B \left (\tan ^{2}\left (d x +c \right )\right )+8 A \tan \left (d x +c \right )+\frac {\left (-8 i A -8 B \right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+\left (8 i B -8 A \right ) \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(168\) |
norman | \(\left (8 i B \,a^{4}-8 A \,a^{4}\right ) x -\frac {\left (4 i A \,a^{4}+7 B \,a^{4}\right ) \left (\tan ^{4}\left (d x +c \right )\right )}{4 d}-\frac {\left (-8 i B \,a^{4}+7 A \,a^{4}\right ) \left (\tan ^{3}\left (d x +c \right )\right )}{3 d}+\frac {8 \left (-i B \,a^{4}+A \,a^{4}\right ) \tan \left (d x +c \right )}{d}+\frac {4 \left (i A \,a^{4}+B \,a^{4}\right ) \left (\tan ^{2}\left (d x +c \right )\right )}{d}+\frac {\left (-4 i B \,a^{4}+A \,a^{4}\right ) \left (\tan ^{5}\left (d x +c \right )\right )}{5 d}+\frac {B \,a^{4} \left (\tan ^{6}\left (d x +c \right )\right )}{6 d}-\frac {4 \left (i A \,a^{4}+B \,a^{4}\right ) \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(194\) |
parallelrisch | \(-\frac {240 i A \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{4}-10 B \,a^{4} \left (\tan ^{6}\left (d x +c \right )\right )-160 i B \left (\tan ^{3}\left (d x +c \right )\right ) a^{4}-12 A \left (\tan ^{5}\left (d x +c \right )\right ) a^{4}-240 i A \left (\tan ^{2}\left (d x +c \right )\right ) a^{4}+105 B \left (\tan ^{4}\left (d x +c \right )\right ) a^{4}+480 i B \tan \left (d x +c \right ) a^{4}+140 A \left (\tan ^{3}\left (d x +c \right )\right ) a^{4}-480 i B x \,a^{4} d +48 i B \left (\tan ^{5}\left (d x +c \right )\right ) a^{4}+480 A x \,a^{4} d +60 i A \left (\tan ^{4}\left (d x +c \right )\right ) a^{4}-240 B \left (\tan ^{2}\left (d x +c \right )\right ) a^{4}-480 A \tan \left (d x +c \right ) a^{4}+240 B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) a^{4}}{60 d}\) | \(214\) |
risch | \(-\frac {16 i a^{4} B c}{d}+\frac {16 a^{4} A c}{d}+\frac {4 a^{4} \left (210 i A \,{\mathrm e}^{10 i \left (d x +c \right )}+270 B \,{\mathrm e}^{10 i \left (d x +c \right )}+765 i A \,{\mathrm e}^{8 i \left (d x +c \right )}+855 B \,{\mathrm e}^{8 i \left (d x +c \right )}+1210 i A \,{\mathrm e}^{6 i \left (d x +c \right )}+1350 B \,{\mathrm e}^{6 i \left (d x +c \right )}+1020 i A \,{\mathrm e}^{4 i \left (d x +c \right )}+1125 B \,{\mathrm e}^{4 i \left (d x +c \right )}+444 i A \,{\mathrm e}^{2 i \left (d x +c \right )}+486 B \,{\mathrm e}^{2 i \left (d x +c \right )}+79 i A +86 B \right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{6}}+\frac {8 a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) B}{d}+\frac {8 i a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) A}{d}\) | \(220\) |
parts | \(\frac {\left (-4 i A \,a^{4}-6 B \,a^{4}\right ) \left (\frac {\left (\tan ^{4}\left (d x +c \right )\right )}{4}-\frac {\left (\tan ^{2}\left (d x +c \right )\right )}{2}+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}\right )}{d}+\frac {\left (-4 i B \,a^{4}+A \,a^{4}\right ) \left (\frac {\left (\tan ^{5}\left (d x +c \right )\right )}{5}-\frac {\left (\tan ^{3}\left (d x +c \right )\right )}{3}+\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {\left (4 i A \,a^{4}+B \,a^{4}\right ) \left (\frac {\left (\tan ^{2}\left (d x +c \right )\right )}{2}-\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}\right )}{d}+\frac {\left (4 i B \,a^{4}-6 A \,a^{4}\right ) \left (\frac {\left (\tan ^{3}\left (d x +c \right )\right )}{3}-\tan \left (d x +c \right )+\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {A \,a^{4} \left (\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )\right )}{d}+\frac {B \,a^{4} \left (\frac {\left (\tan ^{6}\left (d x +c \right )\right )}{6}-\frac {\left (\tan ^{4}\left (d x +c \right )\right )}{4}+\frac {\left (\tan ^{2}\left (d x +c \right )\right )}{2}-\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}\right )}{d}\) | \(268\) |
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Time = 0.25 (sec) , antiderivative size = 345, normalized size of antiderivative = 1.53 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=-\frac {4 \, {\left (30 \, {\left (-7 i \, A - 9 \, B\right )} a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} + 45 \, {\left (-17 i \, A - 19 \, B\right )} a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, {\left (-121 i \, A - 135 \, B\right )} a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, {\left (-68 i \, A - 75 \, B\right )} a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, {\left (-74 i \, A - 81 \, B\right )} a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + {\left (-79 i \, A - 86 \, B\right )} a^{4} + 30 \, {\left ({\left (-i \, A - B\right )} a^{4} e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, {\left (-i \, A - B\right )} a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, {\left (-i \, A - B\right )} a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, {\left (-i \, A - B\right )} a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, {\left (-i \, A - B\right )} a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, {\left (-i \, A - B\right )} a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + {\left (-i \, A - B\right )} a^{4}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )\right )}}{15 \, {\left (d e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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Time = 0.82 (sec) , antiderivative size = 348, normalized size of antiderivative = 1.55 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {8 i a^{4} \left (A - i B\right ) \log {\left (e^{2 i d x} + e^{- 2 i c} \right )}}{d} + \frac {316 i A a^{4} + 344 B a^{4} + \left (1776 i A a^{4} e^{2 i c} + 1944 B a^{4} e^{2 i c}\right ) e^{2 i d x} + \left (4080 i A a^{4} e^{4 i c} + 4500 B a^{4} e^{4 i c}\right ) e^{4 i d x} + \left (4840 i A a^{4} e^{6 i c} + 5400 B a^{4} e^{6 i c}\right ) e^{6 i d x} + \left (3060 i A a^{4} e^{8 i c} + 3420 B a^{4} e^{8 i c}\right ) e^{8 i d x} + \left (840 i A a^{4} e^{10 i c} + 1080 B a^{4} e^{10 i c}\right ) e^{10 i d x}}{15 d e^{12 i c} e^{12 i d x} + 90 d e^{10 i c} e^{10 i d x} + 225 d e^{8 i c} e^{8 i d x} + 300 d e^{6 i c} e^{6 i d x} + 225 d e^{4 i c} e^{4 i d x} + 90 d e^{2 i c} e^{2 i d x} + 15 d} \]
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Time = 0.28 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.67 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {10 \, B a^{4} \tan \left (d x + c\right )^{6} + 12 \, {\left (A - 4 i \, B\right )} a^{4} \tan \left (d x + c\right )^{5} - 15 \, {\left (4 i \, A + 7 \, B\right )} a^{4} \tan \left (d x + c\right )^{4} - 20 \, {\left (7 \, A - 8 i \, B\right )} a^{4} \tan \left (d x + c\right )^{3} - 240 \, {\left (-i \, A - B\right )} a^{4} \tan \left (d x + c\right )^{2} - 480 \, {\left (d x + c\right )} {\left (A - i \, B\right )} a^{4} - 240 \, {\left (i \, A + B\right )} a^{4} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 480 \, {\left (A - i \, B\right )} a^{4} \tan \left (d x + c\right )}{60 \, d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 600 vs. \(2 (195) = 390\).
Time = 0.82 (sec) , antiderivative size = 600, normalized size of antiderivative = 2.67 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=-\frac {4 \, {\left (-30 i \, A a^{4} e^{\left (12 i \, d x + 12 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 30 \, B a^{4} e^{\left (12 i \, d x + 12 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 180 i \, A a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 180 \, B a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 450 i \, A a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 450 \, B a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 600 i \, A a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 600 \, B a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 450 i \, A a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 450 \, B a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 180 i \, A a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 180 \, B a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 210 i \, A a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} - 270 \, B a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} - 765 i \, A a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} - 855 \, B a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} - 1210 i \, A a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} - 1350 \, B a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} - 1020 i \, A a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} - 1125 \, B a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} - 444 i \, A a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} - 486 \, B a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} - 30 i \, A a^{4} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 30 \, B a^{4} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 79 i \, A a^{4} - 86 \, B a^{4}\right )}}{15 \, {\left (d e^{\left (12 i \, d x + 12 i \, c\right )} + 6 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 15 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 20 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 15 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 6 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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Time = 7.54 (sec) , antiderivative size = 308, normalized size of antiderivative = 1.37 \[ \int \tan ^2(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,\left (-a^4\,\left (A-B\,1{}\mathrm {i}\right )+\frac {a^4\,\left (B+A\,3{}\mathrm {i}\right )\,1{}\mathrm {i}}{3}+\frac {B\,a^4\,1{}\mathrm {i}}{3}+\frac {a^4\,\left (3\,B+A\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{3}\right )}{d}-\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (-A\,a^4-3\,a^4\,\left (A-B\,1{}\mathrm {i}\right )+a^4\,\left (B+A\,3{}\mathrm {i}\right )\,1{}\mathrm {i}+B\,a^4\,1{}\mathrm {i}+a^4\,\left (3\,B+A\,1{}\mathrm {i}\right )\,1{}\mathrm {i}\right )}{d}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^5\,\left (\frac {B\,a^4\,1{}\mathrm {i}}{5}+\frac {a^4\,\left (3\,B+A\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{5}\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (8\,B\,a^4+A\,a^4\,8{}\mathrm {i}\right )}{d}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^2\,\left (\frac {A\,a^4\,1{}\mathrm {i}}{2}+\frac {a^4\,\left (A-B\,1{}\mathrm {i}\right )\,3{}\mathrm {i}}{2}+\frac {a^4\,\left (B+A\,3{}\mathrm {i}\right )}{2}+\frac {B\,a^4}{2}+\frac {a^4\,\left (3\,B+A\,1{}\mathrm {i}\right )}{2}\right )}{d}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^4\,\left (\frac {a^4\,\left (A-B\,1{}\mathrm {i}\right )\,3{}\mathrm {i}}{4}+\frac {B\,a^4}{4}+\frac {a^4\,\left (3\,B+A\,1{}\mathrm {i}\right )}{4}\right )}{d}+\frac {B\,a^4\,{\mathrm {tan}\left (c+d\,x\right )}^6}{6\,d} \]
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